To see whether a substance is redox or redox, the key lies in the case of the particles it contains. In potassium hydroxide, potassium has a + 1 valence, so it can only get one electron to be reduced, so it is oxidized. One drawback of the answer is that Oh is not oxidized or reduced. Why? Because what is called electrolysis is not a real reaction process, for example, the reaction of silicon with sodium hydroxide. The equation is sodium hydroxide and hydroxide oxidation, but the oxidant is water. The reaction is misleading, because both lice are written together. Remember, generally speaking, when you get the highest positive valence, you only show oxidation, and when you get the lowest negative valence, you only show reduction.

　　臭氧與氫氧化鉀的反應(yīng)是4KOH+4O3+2H2O=4KO3·H2O+O2

　　The reaction between ozone and potassium hydroxide is 4KOH+4O 3+2H 2=4KO 3.H 2+O 2.

　　的原因是臭氧氧化的反應(yīng)很強(qiáng),有一定的還原性和KOH,反應(yīng)會(huì)產(chǎn)生兩個(gè)橙紅色固體KO3·H2O一水臭卡莉,稱為“臭卡莉】【,O3是減少O2和O3 -氧氣】【】【臭氧根,和原來的氧化態(tài),二也是O3氧化的氧-(部分)。

　　The reason is that the ozone oxidation reaction is very strong, with certain reductivity and KOH. The reaction produces two orange-red solid KO 3 H 2 2 O 3

　　反應(yīng)的本質(zhì)是臭氧的氧化——氧的氧化態(tài),結(jié)果O3的形成和氧氣,但電子的總數(shù)在O3 - 23,順,容易分解,在稀溶液將很快分解成氧氣和KOH,如果它是一個(gè)稀溶液,反應(yīng)產(chǎn)物是氧氣,KOH保持不變。在濃縮液中，KO3·H2O析出為橙紅色固體，然后緩慢分解為KO2[過氧化物鉀]和O2

　　The essence of the reaction is the oxidation of ozone - the oxidation state of oxygen, resulting in the formation of O3 and oxygen, but the total number of electrons in O3 - 23, cis, easy to decompose, in dilute solution will soon decompose into oxygen and KOH, if it is a dilute solution, the reaction product is oxygen, KOH remains unchanged. In the concentrated solution, KO_3 H_2 precipitates into orange solid, then slowly decomposes into KO_2 [potassium peroxide] and O_2.

　　結(jié)論:臭氧與氫氧化鉀反應(yīng)生成氧化鉀和氧。如果溶液很薄，產(chǎn)物就是氧。

　　Conclusion: Ozone reacts with potassium hydroxide to produce potassium oxide and oxygen. If the solution is very thin, the product is oxygen.

　　注:該反應(yīng)也適用于氫氧化銣和氫氧化銫，但不適用于氫氧化鈉，因?yàn)槌粞趸c穩(wěn)定性低，可立即分解為氧和氫氧化鈉。

　　Note: This reaction is also applicable to rubidium hydroxide and cesium hydroxide, but not to sodium hydroxide, because the stability of sodium ozonate is low, it can be immediately decomposed into oxygen and sodium hydroxide.